If you get into trouble, you can usually interrupt Octave by typing Control-C (written C-c for short). C-c gets its name from the fact that you type it by holding down and then pressing . Doing this will normally return you to Octave’s prompt.
octave can work as calculator and support following functions:
cos Cosine of an angle (in radians)
sin Sine of an angle (in radians)
tan Tangent of an angle (in radians)
exp Exponential function (ex)
log Natural logarithm (NB this is loge, not log10)
log10 Logarithm to base 10
sinh Hyperbolic sine
cosh Hyperbolic cosine
tanh Hyperbolic tangent
acos Inverse cosine
acosh Inverse hyperbolic cosine
asin Inverse sine
asinh Inverse hyperbolic sine
atan Inverse tangent
atan2 Two-argument form of inverse tangent
atanh Inverse hyperbolic tangent
abs Absolute value
sign Sign of the number (−1 or +1)
round Round to the nearest integer
floor Round down (towards minus infinity)
ceil Round up (towards plus infinity)
fix Round towards zero
rem Remainder after integer division
Think of making a program which solves the IUPAC equations. the user writes an inbalanced equation and the program generates the balanced equation.
A simple example comes from chemistry and the need to obtain balanced chemical equations. Consider the burning of hydrogen and oxygen to produce water.
H2 + O2 –> H2O
The equation above is not accurate. The Law of Conservation of Mass requires that the number of molecules of each type balance on the left- and right-hand sides of the equation. Writing the variable overall reaction with individual equations for hydrogen and oxygen one finds::)
x1*H2 + x2*O2 –> H2O
H: 2*x1 + 0*x2 –> 2 O: 0*x1 + 2*x2 –> 1
The solution in Octave is found in just three steps.
1> A = [ 2, 0; 0, 2 ];
octave:2> b = [ 2; 1 ];
octave:3> x = A \ b
now, you can save the
equation = H2 + O2 –> H2O
strsplit(equation,”–>”) will divide the equation into two parts:
[1,1] = H2+O2
[1,3] = H20
what if the string have spaces.
octave:15> eq =” H2 + O2 –> H20″
eq = H2 + O2 –> H20
[1,1] = H2 + O2
[1,4] = H20
this variablity of result with variation of input needs to be tackled.
inidividual elements of matrix can be accessed using the following command:
[1,1] = H2 + O2
now, you need to know which element exists in the equation.
this can be easily done:
get the position of alphabets:
0 1 0 0 0 0 1 0 0
get the position of numbers:
0 0 1 0 0 0 0 1 0
now, think of putting everything in a function such that you are able to interpret any equation and make it balanced.
this is the target:
before going further, let’s see an example of function which find the max value in vector. here, a function can return more than one value. in this case, we need to find the maximum value of an element in vector and further it’s index as well.
function [max, idx] = vmax (v)
idx = 1;
max = v (idx);
for i = 2:length (v)
if (v (i) > max)
max = v (i);
idx = i;